See image β AITS & Test Series Chemistry Question
Question
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Answer: B
π‘ Solution & Explanation
C=O -802.8 = 4Γ 416.2 + 2Γ 493.7 - 2Γ ΞH - 4Γ 464.4 ο ο½ C=0 H 798.7 kJ / mol
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