Which is the following pairs of species have identical shapes? — Chemical Bonding Chemistry Question

💡 Solution & Explanation

Step 1: Determine the geometries: NO2^+ is linear and NO2^- is bent; PCl5 is trigonal bipyramidal and BrF5 is square pyramidal; TeCl4 is see-saw and XeO4 is tetrahedral. Step 2: Analyze XeF4 and ICl4^-: both central atoms (Xe and I) have 4 bond pairs and 2 lone pairs, resulting in sp3d2 hybridization and a square planar shape. Step 3: Since both XeF4 and ICl4^- are square planar, they have identical shapes, which matches option (c).