Sodium metal crystallizes in BCC lattice with the cell edge, a = 4.29 A. What is the radius of the s — Solid State Chemistry Question
Question
Sodium metal crystallizes in BCC lattice with the cell edge, a = 4.29 A. What is the radius of the sodium atom?
Answer: A
💡 Solution & Explanation
In BCC: 4r = a*√(3). r = 4.29*1.732/4 = 1.857 A ≈ 1.86 A.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes