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AITS & Test SerieshardMCQ SINGLE

Question

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Answer: A

💡 Solution & Explanation

H N–CH –COOH 2 2 p = 2 H p = 9 H NH –CH –COOH 3 2 + H NCH COO 2 2 – will move towards anode Anionic Cationic SECTION – D

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