I2O5 + H2O -> HIO3 — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Step 1: Diiodine pentoxide (I2O5) is the anhydride of iodic acid, with iodine in the +5 oxidation state. Step 2: Dissolving I2O5 in water leads to a simple non-redox hydration reaction to form iodic acid (HIO3). Step 3: Since the resulting oxyacid is iodic acid, which ends in '-ic', this reaction is classified as category A.