Given below are two statements : Statement-I : The limiting molar conductivity of KCl (strong electrolyte) is higher compared to that of CH3COOH (weak electrolyte). Statement-II : Molar conductivity d

Question

Given below are two statements : Statement-I : The limiting molar conductivity of KCl (strong electrolyte) is higher compared to that of CH3COOH (weak electrolyte). Statement-II : Molar conductivity decreases with decrease in concentration of electrolyte. In the light of the above statements, choose the most appropriate answer from the options given below :

(A) Statement-I is true but Statement-II is false
(B) Both Statement-I and Statement-II are true
(C) Statement-I is false but Statement-II is true
(D) Both Statement-I and Statement-II are false | JEE MAIN-2021 | DATE : 26-08-2021 (SHIFT-1) | PAPER-1 | OFFICIAL PAPER | CHEMISTRY PAGE # 4 uhps nks dFku fn;k gS& dFku-I : KCl (izcy oS|qr vi?kV~;) dh lhekar eksyj pkydrk CH3COOH (nqcZy oS|qr vi?kV~;) ds eku dh rqyuk esa vf/kd gSA dFku-II : fo|qr vi?kV~; dh lkUnzrk ?kVus ij eksyj pkydrk ?kV tkrh gSA mijksDr dFkuksa ds lanHkZ esa uhps fn, fodYiksa esa lg lgh mÙkj pqfu,A (1) dFku-I lR; gSa ijUrq dFku-II vlR; gSA (2) nksuksa dFku-I rFkk dFku-II lR; gSA (3) dFku-I vlR; gS ijUrq dFku-II lR; gSA (4) nksuksa dFku-I rFkk dFku-II vlR; gSA

Prashant Kotian · Accepted Answer

Correct answer: D. Ion K+ Cl– CH3COO– H+ º/(S cm2mol–1) 73.5 76.3 40.9 349.6 ºM(CH3COOH) = ºM(H+) + ºM(CH3COO–) = 349.6 + 40.9 = 390.5 S cm2mol–1 ºM(KCl) = ºM(K+) + ºM(Cl–) = 73.5 + 76.3 = 149.8 S cm2mol–1 So, statement-I is false. For an electrolyte the dilution increases (or) decrease in concentration, the number of ions increases due to increase of degree of dissociation. So, the molar conductance increases. Hence Statement-II is false.

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