Correct answer: 15. NaOBr 2 2 2 NH CONH N , 22400 mL at NTP 60 g urea   3 3 60

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AITS & Test SerieshardNUMERICAL

Question

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Answer: 15

💡 Solution & Explanation

NaOBr 2 2 2 NH CONH N , 22400 mL at NTP 60 g urea   3 3 60

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