See image — IUPAC and Nomenclature Chemistry Question

💡 Solution & Explanation

Step 1 - Identify the parent structure: The molecule shown is a benzene ring bearing a hydroxyl (OH) substituent, making the parent compound phenol. The OH group defines C1 by convention. Step 2 - Locate the bromine substituents: Three bromine atoms are attached to the ring. One Br is on the carbon immediately to the left of the OH-bearing carbon (C2), one Br is on the carbon immediately to the right of the OH-bearing carbon (C6), and one Br is on the carbon directly opposite the OH group (C4). Step 3 - Apply IUPAC numbering: In phenol, the carbon bearing the OH is C1. Numbering proceeds to give the substituents the lowest possible locants. The two bromines flanking the OH are at C2 and C6, and the bromine para to the OH is at C4. Step 4 - Construct the name: The parent is phenol (hydroxybenzene). The three bromine substituents are at positions 2, 4, and 6. The complete IUPAC name is 2,4,6-tribromophenol. Step 5 - Verify symmetry: The molecule is symmetric about the axis passing through C1 (OH) and C4 (Br), confirming the 2,4,6 substitution pattern. Therefore, the correct answer is 2,4,6-tribromophenol.