If 75% of a first order reaction was completed in 90 minutes, 60% of the same reaction would be completed in approximately (in minutes) ………….. (Take : log 2 = 0.30 ; log 2.5 = 0.40)

Question

Prashant Kotian · Accepted Answer

Correct answer: .. T = K . log     % x 100 T75% = K . log     100 = 90 T60% = K . log     100 % % T T = . log log  % T = . 3 . 2 T60% = 4 90 = 60 min.

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