Enthalpy of neutralization of the reaction between CH3COOH(aq) and (aq) is -13.2 kcal/eq and that of β Thermodynamics and Thermochemistry Chemistry Question
Question
Enthalpy of neutralization of the reaction between CH3COOH(aq) and $NaOH$(aq) is -13.2 kcal/eq and that of the reaction between $H_2SO_4$(aq) and $KOH$(aq) is -13.7 kcal/eq. The enthalpy of dissociation of CH3COOH(aq) is
Answer: B
π‘ Solution & Explanation
The neutralization of strong acid and strong base (like $H_2SO_4$ + $KOH$) has an enthalpy of -13.7 kcal/eq. CH3COOH is a weak acid, so its neutralization releases less heat (-13.2 kcal/eq). The difference of 0.5 kcal/eq is the enthalpy of dissociation of CH3COOH. Thus, enthalpy of dissociation is +0.5 kcal/eq.
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