See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

(A) 0 D  therefore range cannot be  0,because leading coefficient ' ' a must also be positive (B) 0, ,2 0, ,2 9orderedpairs x y        (C) 2 2 2 a c b bc    2 cos 3 bc A bc A    AM GM  minimum value is 4