See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Maximum number of points of intersection possible if there are no constraints 20 2 C 190   . But 5 of these 20 lines are parallel. There will not be any intersection point from these 5 lines.  Maximum number of points of intersection 5 2 190 C 180    . Also the times 1 5 9 13 17 L ,L ,L ,L ,L pass through one point.  We need to replace   5 2 C 10  points by 1.  The maximum number of points of intersection 190 10 10 1 171      SECTION – C