Consider the following electrochemical cell at standard condition. Au(s)|QH2, Q|NH4X(0.01 M) || Ag+( — JEE Mains Chemistry Past Papers Chemistry Question
Question
Consider the following electrochemical cell at standard condition. Au(s)|QH2, Q|NH4X(0.01 M) || Ag+(1 M) | Ag(s) Ecell = + 0.4 V The couple QH2/Q represents quinhydrone electrode, the half cell reaction is given below : [Given : Ag / Ag E = +0.8 V and F RT . = 0.06 V] The pKb value of the ammonium halide salt (NH4X) used here is________. (nearest integer)
Answer: .
💡 Solution & Explanation
From Nernst equation 0.4 = (0.8 – 0.7) – 06 . log 2 ] Ag [ ] H [ [H+] = 10–5 M = b K 01 . so Kb = 10–6. So pKb = 6
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