Match List-I with List-II List-I List-II (a) [Fe(CN)6]3– (i) 5.92 BM (b) [Fe(H2O)6]3+ (ii) 0 BM (c) [Fe(CN)6]4– (iii) 4.90 BM (d) [Fe(H2O)6]2+ (iv) 1.73 BM Choose the correct answer from the options g

Question

Match List-I with List-II List-I List-II (a) [Fe(CN)6]3– (i) 5.92 BM (b) [Fe(H2O)6]3+ (ii) 0 BM (c) [Fe(CN)6]4– (iii) 4.90 BM (d) [Fe(H2O)6]2+ (iv) 1.73 BM Choose the correct answer from the options given below

(A) (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
(B) (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
(C) (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
(D) (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)

Prashant Kotian · Accepted Answer

Correct answer: D. [Fe(CN)6]–3 Fe+3 = 3d5 Unpaired electron = 1, µ = 1.7 BM [Fe(H2O)6]+3 Fe+3 = 3d5 Unpaired electrons = 5, µ = 5.9 BM [Fe(CN)6]–4 Fe+2 = 3d6 Unpaired electron = 0, µ = 0 BM [Fe(H2O)6]+2 Fe+2 = 3d6 Unpaired electrons = 4, µ = 4.9 BM

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