CrCl3.xNH3 can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of 0.558ºC. Assuming 100% ionisation of this complex and coordination number of Cr is

Question

CrCl3.xNH3 can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of 0.558ºC. Assuming 100% ionisation of this complex and coordination number of Cr is 6, the complex will be (Given Kf = 1.86 K kg mol–1)

(A) [Cr(NH3)3Cl3]
(B) [Cr(NH3)6Cl3]
(C) [Cr(NH3)4Cl2]Cl
(D) [Cr(NH3)5Cl]Cl2

Prashant Kotian · Accepted Answer

Correct answer: D. CrCl3 × NH3 : Tf = i. Kf . m 0.558 - I × 1.86 × 0.1 I = 3  CrCl3. × NH3 = [Cr(NH3)5Cl]Cl2

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