[Four-digit Integer] The rate constant for the decomposition of ozone following second-order kinetic — Chemical Kinetics Chemistry Question
Question
[Four-digit Integer] The rate constant for the decomposition of ozone following second-order kinetics is 5 × 10⁻⁴ L mol⁻¹ s⁻¹ at a certain temperature. The rate of reaction (in terms of number of molecules decomposed per ml per minute, when concentration of ozone is 2 × 10⁻⁶ M) is: (NA = 6 × 10²³)
Answer: 7200
💡 Solution & Explanation
Rate = K[$O_3$]² = 5×10⁻⁴ × (2×10⁻⁶)² = 2×10⁻¹⁵ mol/L/s. Molecules/L/s = 2×10⁻¹⁵ × 6×10²³ = 1.2×10⁹. Per ml per min = (1.2×10⁹/10³) × 60 = 7.2×10⁷.
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