Given below are two statement : Statement : One mole of propyne reacts with excess of sodium to liberate half a mole of H2 gas. Statement : Four g of propyne reacts with NaNH2 to liberate NH3 gas whic

Question

Given below are two statement : Statement : One mole of propyne reacts with excess of sodium to liberate half a mole of H2 gas. Statement : Four g of propyne reacts with NaNH2 to liberate NH3 gas which occupies 224 mL at STP. In the light of the above statements, choose the most appropriate answer from the options given below.

(A) Statement is correct but Statement is incorrect
(B) Both Statement and Statement are incorrect
(C) Statement is incorrect but Statement is correct
(D) Both Statement and Statement are correct

Prashant Kotian · Accepted Answer

Correct answer: A. CH3C CH + Na  2 1 H2 + CH3 – C  C– Na CH3–CCH + NaNH2  NH3(g) NH3 = 224 ml = 10–2 mol Hence 10–2 × 40 g = 0.4g propyne.

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