See image — IUPAC and Nomenclature Chemistry Question

💡 Solution & Explanation

Step 1: Identify the functional group. The structure contains a C=O group connected to an NH, making it an amide (CONH). This means we name it as an 'amide' with an 'N-substituent' prefix. Step 2: Identify the acyl (acid-derived) portion. On the carbonyl side, we count the longest chain including the carbonyl carbon: C(=O)-CH2-CH(Br)-CH(Br)-CH3. This is a 5-carbon chain (pentanoyl), so the parent acid is pentanoic acid, giving the base name 'pentanamide'. Step 3: Number the acyl chain. C1 is the carbonyl carbon. Going along the chain: C1(=O), C2(H2), C3(Br)(H), C4(Br)(H), C5(H3). Bromine substituents are at C3 and C4, giving '3,4-dibromopentanamide'. Step 4: Identify the N-substituent. On the nitrogen side: NH-CH2-CH2-CH(Br)-CH2Br. This is a 4-carbon group (butyl) with bromo substituents. Counting from the nitrogen attachment: C1(H2), C2(H2), C3(Br)(H), C4(H2Br). Bromine substituents are at C3 and C4, giving '3,4-dibromobutyl'. Step 5: Combine. The N-substituent is named with the 'N-' prefix: N-(3,4-dibromobutyl). The full IUPAC name is 3,4-dibromo-N-(3,4-dibromobutyl)pentanamide. Therefore, the correct answer is 3,4-dibromo-N-(3,4-dibromobutyl)pentanamide.