See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

143 kcal / mole     2 5H   Stable resonating structure 2 Naphthalene 5H   H 82 kcal / mole       resonance naphthalene H 143 82 61     Resonance energy of benzene = - 36 One naphthalene ring equivalent to two benzene ring  Magnitude of resonance energy of naphthalene (-61), is less than two benzene ring (-72). So benzene ring is more stable. SECTION – C