See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

∆T = 5.51 1.59 = 3.92, w = 0.186 g W = 7.5g, kf = 4.9 k 1 molality   f 1000 x K x w T m x W  3.92 = 1000 x 4.9 x 0.186 m x 7.5 @bohring_bot AITS-FT-II-PCM(Sol.)-JEE(Main)/2024 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 11  m = 136 g 1 mol