Match List-I with List-II. List-I List-II A. Coke I. Carbon atoms are sp3 hybridised B. Diamond II. — NEET Chemistry Past Papers Chemistry Question
Question
Match List-I with List-II. List-I List-II A. Coke I. Carbon atoms are sp3 hybridised B. Diamond II. Used as a dry lubricant C. Fullerene III. Used as a reducing agent D. Graphite IV. Cage like molecules Choose the correct answer from the options given below: (A) A-IV, B-I, C-II, D-III (B) A-III, B-I, C-IV, D-II (C) A-III, B-IV, C-I, D-II (D) A-II, B-IV, C-I, D-III
💡 Solution & Explanation
Coke : It is used as reducing agent in carbon reduction methods. (in metallurgical process) Diamond : It is a allotrope of carbon in which each carbon is sp3 hybridised. Fullerene : It contains pentagonal & hexagonal rings (cage like structure) Graphite : It is soft solid because graphite layers are bonded with weak Vander Wall attractions.