2 moles each of ethylene glycol and glucose are dissolved in 500 g of water. The boiling point of th — JEE Mains Chemistry Past Papers Chemistry Question
Question
2 moles each of ethylene glycol and glucose are dissolved in 500 g of water. The boiling point of the resulting solution is: (Given: Ebullioscopic constant of water = 0.52 K kg mol–1) (A) 277.3 K (B) 375.3 K (C) 379.2 K (D) 377.3 K
Answer: D
💡 Solution & Explanation
Tb = kb × m = 0.52 × . 4 (T’b = 373) = 4.16 T’b = 377.16 K
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes