In polymeric (BeCl2)n, there are : — s Block Elements Chemistry Question

💡 Solution & Explanation

Step 1: The solubility of Group 2 fluorides is dictated by the competition between lattice enthalpy and hydration enthalpy down the group. Step 2: Because Be^2+ is extremely small, its hydration enthalpy is incredibly large and easily overcomes the lattice enthalpy of BeF2. Step 3: Moving down the group, the hydration enthalpy decreases much faster than the lattice enthalpy, making BeF2 the most soluble fluoride, corresponding to option (d).