See image — AITS & Test Series Chemistry Question
Question
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Answer: A
💡 Solution & Explanation
] Y [] X [ ] Z [ K c a ] Z [ 2 1 ] Y [ 2 1 ] X [ (let) [Z] = 2a, [Y] = 2a, [X] = a 104 = a 2 a a 2 a = 10–4 [Z] = 2a = 2 × 10–4 mol L1.
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