See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

   2X g 2Y g Z g    1 -   2  Total moles = 2 1 2 2          2 Y Z P 2 X P P K P        2 2 2 2 2 P . P 2 2 2 1 P 2                              neglecting  compared to 1 and solving 1/3 P 2K n 3 P         