t_1/2 of a reaction: A -> Products (order = 3/2) is represented by t_1/2 ∝ 1/[A_0]^m. The value of m — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

The half-life is related to the initial concentration by t_1/2 ∝ [A_0]^(1-n). For a reaction of order n = 3/2: t_1/2 ∝ [A_0]^(1 - 1.5) = [A_0]^(-0.5) = 1/[A_0]^0.5. Comparing this with t_1/2 ∝ 1/[A_0]^m, we get m = 0.5.