SrCrO4β + 2AcOH (Excess) -> Sr(AcO)2 + H2Cr2O7 β Redox Reactions and Volumetric Analysis Chemistry Question
Question
SrCrO4β + 2AcOH (Excess) -> Sr(AcO)2 + H2Cr2O7
Answer: B
π‘ Solution & Explanation
Step 1: Identify that strontium chromate, SrCrO4β, is an insoluble precipitate. Step 2: Acetic acid (AcOH), when added in excess, provides sufficient acidity to convert chromate ions to soluble dichromate species, thereby dissolving the strontium chromate precipitate to form soluble strontium acetate, Sr(AcO)2. Step 3: Because the solid precipitate is dissolved by the acid to yield a clear solution, this is a precipitate dissolution reaction (type B), matching option (b).
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