The molar conductivity of 0.007 M acetic acid is 20 S cm2 mol–1. What is the dissociation constant of acetic acid ? Choose the correct option. – 3 o 2 –1 H o 2 –1 CH COO 350Scm mol 50Scm mol + é ù L =

Question

The molar conductivity of 0.007 M acetic acid is 20 S cm2 mol–1. What is the dissociation constant of acetic acid ? Choose the correct option. – 3 o 2 –1 H o 2 –1 CH COO 350Scm mol 50Scm mol + é ù L = ê ú L = ê ú ë û

(A) 1.75 × 10–4 mol L–1
(B) 2.50 × 10–4 mol L–1
(C) 1.75 × 10–5 mol L–1
(D) 2.50 × 10–5 mol L–1

Prashant Kotian · Accepted Answer

Correct answer: C. + L = L + L 3 – (H ) (CH COO ) 3 0 0 0 M(CH COOH) M M = 350 + 50 = 400 Scm2mol–1 L a = L C M 0 M a = = ´ –2 20 5 10 400 3 2 a(CH COOH) K C = a = 0.007 × (5 × 10–2)2 = 1.75 × 10–5 mol L–1

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