When a hydrocarbon A undergoes complete combustion it requires 11 equivalents of oxygen and produces — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

CxHy +       4 y x O2 CO2 + y H2O a        y x a       y a given       4 y x a = 11a y x  = 11       y a = 4a y = 8, Then x + 8/4 = 11 x = 9 Formula = C9H8 | JEE(Main) 2023 | DATE : 31-01-2023 (SHIFT-2) | PAPER-1 | OFFICIAL PAPER | CHEMISTRY PAGE # 2