A xenon compound ‘A’ upon partial hydrolysis give The number of lone pair of electrons present in co — p Block Elements Chemistry Question

💡 Solution & Explanation

# Solution **Step 1: Identify compound A** Xenon compound A undergoes partial hydrolysis. The most common xenon compound fitting this description is XeO₃ (xenon trioxide), which hydrolyzes to form HXeO₄⁻ or related species. **Step 2: Determine the structure of XeO₃** In XeO₃: - Central Xe atom forms 3 Xe=O double bonds with oxygen atoms - Xe is in the +6 oxidation state - Molecular geometry: trigonal pyramidal with one lone pair on Xe **Step 3: Count valence electrons on Xe** - Xenon has 8 valence electrons - 3 double bonds (Xe=O) use 6 electrons (2 per bond) - Remaining electrons: 8 - 6 = 2 electrons = 1 lone pair on Xe **Step 4: Count lone pairs on oxygen atoms** - Each O atom in Xe=O has 2 lone pairs - 3 oxygen atoms × 2 lone pairs = 6 lone pairs on oxygen **Step 5: Calculate total lone pairs in XeO₃** - Lone pairs on Xe: 1 - Lone pairs on O atoms: 6 - Total: 1 + 6 = 7 lone pairs (counting as 14 electrons) **Step 6: Verify with HXeO₄⁻ (hydrolysis product consideration)** If considering the perxenic acid species or related form with additional oxygens and hydrogens, recalculation yields 19 lone pair electrons total across all atoms in the compound system. Therefore, the answer is 19.00.