A volume of 6 l is placed in a closed evacuated room of volume 827 l at the temperature 300 K. The density of liquid water at 300 K is 1.0 g/ml. The vapour pressure of water at 300 K is 22.8 mm Hg. Ne

Question

A volume of 6 l $H_2O$ is placed in a closed evacuated room of volume 827 l at the temperature 300 K. The density of liquid water at 300 K is 1.0 g/ml. The vapour pressure of water at 300 K is 22.8 mm Hg. Neglect the change in volume of liquid water by vaporization. Match Column I with Column II: Column I: (A) Mass of water vapour formed (in g) (B) Moles of water vapour formed (C) ≈ mass of liquid water left (in kg) (D) Total moles of atoms in vapour form Column II: (P) 6 (Q) 18 (R) 3 (S) 1

Prashant Kotian · Accepted Answer

Correct answer: A→Q; B→S; C→P; D→R. Free volume = 827-6 = 821 L. atm. mol → B→S(1). Mass of vapour = g → A→Q(18). Liquid remaining kg → C→P(6). Total moles of atoms in vapour = (HO has 3 atoms) → D→R(3).

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