See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

      2 2 7x 7x 3x 3x e 1 e 1 e 6 e 0        let 7x 3x e 1 t, e s    t2 – ts – 6s2 = 0     t 3s t 2s 0     t = 3s, or t + 2s = 0  7x 3x e 1 3e   or 7x 3x e 1 2e 0   4x 3x e e 3    Let g(x) = e4x – e–3x  g x 0   Only one solution g(x) y = 3 or 7x 3x e 2e 1    7x 3x h x e 2e    h x 0   Only one solution Hence total number of real solutions two (0, 3) h(x) y = 1 TG ~ @bohring_bot TG ~ @bohring_bot | @HeyitsyashXD AITS-PT-I (Paper-1)-PCM(Sol.)-JEE(Advanced)/2025 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 18