See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let V be the initial volume of the balloon, and M be its mass. Weight of water displaced = weight of balloon i.e. Mg g V   3 2 or   V M 3 2 Now, let the depth of immersion be h m, so that the new pressure = (10 + h) m of water. Applying Boyle’s law 2 2 1 1 V P V P  i.e., 10V =   V h) 10 (  V M  h = 5 m