H4B2O6 + H2O -> H3BO3 + H2O2 — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Step 1: Hypoboric acid (H4B2O6) contains a B-B or B-O-O-B linkage with boron in the +3 oxidation state. Step 2: Hydrolysis cleaves the bridging linkage, producing orthoboric acid (H3BO3) along with hydrogen peroxide (H2O2). Step 3: Because the boron-containing product is boric acid, which ends with the '-ic' suffix, this reaction is categorized as type A.