The graph of log m x vs log p for an adsorption process is a straight line inclined at an angle of 45º with intercept equal to 0.6020. The mass of gas adsorbed per unit mass of adsorbent at the pressu

Question

The graph of log m x vs log p for an adsorption process is a straight line inclined at an angle of 45º with intercept equal to 0.6020. The mass of gas adsorbed per unit mass of adsorbent at the pressure of 0.4 atm is ______ × 10–1 (Nearest integer). Given: log 2 = 0.3010

Prashant Kotian · Accepted Answer

Correct answer: .. n kP m x  log(x/m) = logk + n 1 logP log (x/m) vs logP graph will be straight ling with slope = n 1 = tan45º = 1 y = intercept = log k1 = 0.6020 = log 4  k = 4 log m x = log4 + log 0.4 log m x = log 1.6 m x = 1.6  16 × 10–1 | JEE(Main) 2023 | DATE : 30-01-2023 (SHIFT-2) | PAPER-1 | CHEMISTRY PAGE # 9

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