The graph of log m x vs log p for an adsorption process is a straight line inclined at an angle of 4 — JEE Mains Chemistry Past Papers Chemistry Question
Question
The graph of log m x vs log p for an adsorption process is a straight line inclined at an angle of 45º with intercept equal to 0.6020. The mass of gas adsorbed per unit mass of adsorbent at the pressure of 0.4 atm is ______ × 10–1 (Nearest integer). Given: log 2 = 0.3010
Answer: .
💡 Solution & Explanation
n kP m x log(x/m) = logk + n 1 logP log (x/m) vs logP graph will be straight ling with slope = n 1 = tan45º = 1 y = intercept = log k1 = 0.6020 = log 4 k = 4 log m x = log4 + log 0.4 log m x = log 1.6 m x = 1.6 16 × 10–1 | JEE(Main) 2023 | DATE : 30-01-2023 (SHIFT-2) | PAPER-1 | CHEMISTRY PAGE # 9
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes