See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

PA = PB XA . 0 PA = XB. 0 PB 0 0 A B B A X P X P  0 0 1 1 A B B A X P X P   0 0 0 1 A B B A P P X P   XB = 0 0 0 A A B P P P  Similarly, 0 0 0 B A A B P X P P   PT = 0 0 0 0 0 0 2 . . . . A A A B B A P P P X P X P P   B B