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AITS & Test SerieshardNUMERICAL

Question

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Answer: 00002.40

💡 Solution & Explanation

C H3 CH3 0 54 44' A B C 0 0 0 CB Sin(54 44')= AC Terminal carbon carbon distance= 2 CB =2 1.5 Sin(54 44') =2 1.5

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