Complex A has a composition of H12O6Cl3Cr. If the complex on treatment with conc. H2SO4 loses 13.5% — JEE Mains Chemistry Past Papers Chemistry Question
Question
Complex A has a composition of H12O6Cl3Cr. If the complex on treatment with conc. H2SO4 loses 13.5% of its original mass, the correct molecular formulas of A is: [Given : atomic mass of Cr = 52 amu and Cl = 35 amu] (A) [Cr(H2O6]Cl3 (B) [Cr(H2O)4Cl2]Cl 2H2O (C) [Cr(H2O)3Cl3] 3H2O (D) [Cr(H2O)5Cl]Cl2 H2O
Answer: B
💡 Solution & Explanation
Conc. H2SO4 acts as dehydrating agent. Molar mass of given complex = 266.5 g/mol. On treating with conc. H2SO4 the mass lost by the complex = g ) . ( 5 . = 2 moles of H2O Formula of the complex = [Cr(H2O)4Cl2]Cl 2H2O
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