Total number of ions from the following with noble gas configuration is _________. Sr2+ (Z = 38), Cs β JEE Mains Chemistry Past Papers Chemistry Question
Question
Total number of ions from the following with noble gas configuration is _________. Sr2+ (Z = 38), Cs+ (Z = 55), La2+ (Z = 57) Pb2+ (Z = 82), Yb2+ (Z = 70) and Fe2+ (Z = 26)
Answer: .
π‘ Solution & Explanation
Noble gas configuration = ns2 np6 [Sr2+] = [Kr] [Cs+] = [Xe] [Yb2+] = [Xe] 4f14 [La2+] = [Xe] 5d1 [Pb2+] = [Xe] 4f14 5d10 6s2 [Fe2+] = [Ar] 3d6
π¬Ask on WhatsApp β
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp β gets answered in minutes