At very high pressure, the compressibility factor of 1 mole of a van der Waal's gas can be given as — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

At very high pressure, the attractive force term a/V^2 is negligible compared to P, so the van der Waals equation simplifies to P(V - b) = RT. Rearranging gives: PV - Pb = RT → PV = RT + Pb → Z = PV/RT = 1 + bP/RT. Also, since P = RT/(V-b), we can substitute this into Z = PV/RT to get Z = [RT/(V-b)] × V / RT = V/(V-b).