A thin tube of uniform cross section has trapped air columns of lengths 46 and 44.5 cm above and below a middle pellet of mercury 5 cm in length when held at an angle of 60° to the vertical. When plac

Question

A thin tube of uniform cross section has trapped air columns of lengths 46 and 44.5 cm above and below a middle pellet of mercury 5 cm in length when held at an angle of 60° to the vertical. When placed horizontally, the columns are equal in length. The temperature is 27°C. The pressure of air columns, in cm Hg, when the tube is horizontal, is

Prashant Kotian · Accepted Answer

Correct answer: D. Mercury contributes 5 × cos60° = 2.5 cm Hg along tube. Total air = 90.5 cm → horizontal length each = 45.25 cm. Boyle's Law: P_h × 45.25 × (1/44.5 - 1/46) = 2.5 → P_h = 75.4 cm Hg.

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