See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

6 2 4 4 XeF SiO XeOF SiF    o 300 C 4 2 2 XeOF H Xe H O HF     o 300 C 2 2 2 2 XeO F H Xe H O HF     3 XeO disproportionate in strongly basic medium. SECTION – B