In a glass tube of 1 m length and uniform cross section, (g) from one end and BF3(g) from the other — States of Matter and Gaseous State Chemistry Question
Question
In a glass tube of 1 m length and uniform cross section, $NH_3$(g) from one end and BF3(g) from the other end are sent at a time. The distance from the ammonia end where the addition compound, BF3·$NH_3$ will first form is (B = 11; F = 19)
Answer: A
💡 Solution & Explanation
M_NH3 = 17, M_BF3 = 11 + 57 = 68 . r_NH3 / r_BF3 = √(68/17) = 2 . Let $NH_3$ travel x cm and BF3 travel 100-x cm. x / (100-x) = 2 => x = 66.67 cm .
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