Study the following thermochemical equations: A -> B; δ H = +100 kcal; B -> C; δ H = -80 kcal. The c — Thermodynamics and Thermochemistry Chemistry Question
Question
Study the following thermochemical equations: A -> B; δ H = +100 kcal; B -> C; δ H = -80 kcal. The correct order of enthalpies of formation of A, B and C is
Answer: B
💡 Solution & Explanation
Let H_A, H_B, H_C be the enthalpies. From the equations: H_B - H_A = 100 => H_B = H_A + 100. H_C - H_B = -80 => H_C = H_B - 80 = (H_A + 100) - 80 = H_A + 20. Comparing these: H_A < H_C < H_B. Thus, the order is A < C < B.
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