See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

2 3 2 7 2 Cr O 14H 6e 2Cr 7H O;           2 2Cl Cl 2e 3      2 3 2 7 2 2 Cr O 14H 6Cl 2Cr 3Cl 7H O;            o cell E