The electron in the nth orbit of Li2+ is excited to (n + 1) orbit using the radiation of energy 1.47 × 10–17 J (as shown in the diagrarn). The value of n is __________ Given: RH = 2.18 × 10–18 J

Question

Prashant Kotian · Accepted Answer

Correct answer: .. E = RHZ2        2 1 n n or 1.47 x 10–17 = 2.18 x 10–18 x 9         2 )1 n ( n on solving n = 1

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