A B The molecule A change into its isomeric form B by following a first order kinetics at a temperat — JEE Mains Chemistry Past Papers Chemistry Question

Question

A B The molecule A change into its isomeric form B by following a first order kinetics at a temperature of 1000 K. If the energy barrier with respect to reactant energy for such isomeric transformation is 191.48 kJ mol– 1 and the frequency factor is 1020, the time required for 50% molecules of A to become B is _______ picoseconds (nearest integer). [R = 8.314 J K–1 mol–1] A B 1000 K ij izFke dksfV cyxfrdh dk ikyu djrs gq, v.kq A vius dks leko;oh :i B esa ifjofrZr djrk gSA ;fn ml leko;oh :ikUrj.k gsrq vfHkdkjd ÅtkZ ds lanHkZ esa ÅtkZ izfrjks/k 191.48 kJ mol–1 rFkk vko`fr xq.kd 1020 gS rks A ds 50% v.kqvksa ds B esa ifjorZu esa yxk le; _______ fidkslsdsUM gSA (fudVre iw.kk±d). [R = 8.314 J K–1 mol–1]