Light green (Compound 'A') White Residue (B) C + D + E (i) 'D' and 'E' are two acidic gas. (ii) 'D' is passed through HgCl2 solution to give yellow ppt. (iii) 'E' is passed through water first and the

Question

Light green (Compound 'A') $\xrightarrow{\Delta}$ White Residue (B) 
$\xrightarrow{	ext{High Temp.}}$ C + D + E
(i) 'D' and 'E' are two acidic gas.
(ii) 'D' is passed through HgCl2 solution to give yellow ppt.
(iii) 'E' is passed through water first and then H2S is passed, white turbidity 
is obtained.
(iv) A is water soluble and addition of HgCl2 in it, yellow ppt is obtained but 
white ppt does not turn into grey on addition of excess solution of 'A'. [1]

Prashant Kotian · Accepted Answer

Correct answer: C. Step 1: Rusting of iron is an electrochemical process occurring in the presence of water and oxygen. Step 2: Iron is oxidized to Fe^2+ and then to Fe^3+, which ultimately precipitates as a hydrated form of iron(III) oxide. Step 3: The chemical composition of rust is hydrated iron(III) oxide, represented as Fe2O3.xH2O, which corresponds to option (c).

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