JEE Mains Chemistry Past PapershardNUMERICAL

100 g of propane is completely reacted with 1000 g of oxygen. The mole fraction of carbon dioxide inJEE Mains Chemistry Past Papers Chemistry Question

Question

100 g of propane is completely reacted with 1000 g of oxygen. The mole fraction of carbon dioxide in the resulting mixture is x × 10–2. The value of x is _____ . (Integer answer) 100 g izksisu dh 1000 g vkWDlhtu ls iw.kZ vfHkfØ;k dh tkrh gSA dkcZu MkbvkWDlkbM dk mRiUu feJ.k esa eksy va'k gS x × 10–2, x dk eku gS _____ . (fudVre iw.kk±d esa)

Answer: .

💡 Solution & Explanation

C3H8(g) + 5O2(g)  3CO2(g) + 4H2O() t = 0 2.27 mole 31.25 mol t =  19.9 mol 6.81 mol 9.08 mol mole fraction of CO2 in the final reaction mixture (heterogenous) . 81 . 9 . 81 . X CO    = 0.1902 = 19.02 × 10–2  19

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