Inorganic benzene reacts with HCl to form a compound B3N3H9Cl3. The protonation occurs at : — Chemical Bonding Chemistry Question

💡 Solution & Explanation

Step 1: Identify that inorganic benzene (borazine, B3N3H6) contains highly polar B-N polar double bonds. Step 2: Because Nitrogen is significantly more electronegative than Boron, the electron density of the delocalized pi system is shifted heavily toward the Nitrogen atoms, making Nitrogen nucleophilic and basic. Step 3: Therefore, when reacting with HCl, protonation (H+ addition) occurs directly at the basic Nitrogen atoms, while the chloride ions attack the electropositive Boron atoms. This corresponds to option (b).